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A balloon is inflated from 0.0100 l to 0.500 l against an external pressure of 10.00 atm. how much work is done in joules? 101.3 j = 1 l atm

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W0lf93
Answer: P(V2-V1) 10(.5-.01) 10(.49) =4.9 L x ATM (101.3)= 496.37 J

Answer:

-496.37 J

Explanation:

P(V2-V1) = 10(.5-.01)

10(.49) =4.9

L x ATM = 4.9 x 101.3= 496.37 J

External pressure means negative therefore its -496.37J

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