sharonnnnnnnb3978 sharonnnnnnnb3978
  • 23-10-2017
  • Physics
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A lightbulb has a resistance of 285 ω when operating with a potential difference of 110 v across it. what is the current in the lightbulb?

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AL2006
AL2006 AL2006
  • 23-10-2017

Current = voltage / resistance

             =   110 v / 285 Ω

             =      0.386 Ampere  (rounded)
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