ladybug6
ladybug6
24-09-2015
Mathematics
contestada
HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP
Respuesta :
Panoyin
Panoyin
25-09-2015
[tex]f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3[/tex]
[tex]f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5[/tex]
[tex]f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}[/tex]
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