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  • 23-08-2015
  • Mathematics
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Using substitution J-3k=3 j=-k+15

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konrad509
konrad509 konrad509
  • 23-08-2015
[tex]j-3k=3\\ j=-k+15\\\\ -k+15-3k=3\\ -4k=-12\\ k=3\\\\ j=-3+15\\ j=12[/tex]
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