(3+2i)(a+bi)=17+7i remember i²=-1 so expand and solve a is the ral part bi is the imaginary part ok so if Ac+Be=dc+fe where c=c and e=e then A=d and B=f
(3+2i)(a+bi)=17+7i expand/distribute/FOIL 3a+2ai+3bi+2bi²=17+7i 3a+2bi+2ai+2bi=17+7i 3a-2b+2ai+2bi=17+7i real parts are 3a-2b imaginary is 2ai+2bi so
3a-2b=17 and 2ai+2bi=7i
we need to solve 2nd equation, divide both sides by i 2a+2b=7 multiply by -1 and add to other equation
