Relax

Respuesta :

Given the expression :

[tex]216x^3-1[/tex]

We need to factor the given expression, it it a difference of cubic :

So, we should know that :

[tex]x^3-a^3=(x-a)\cdot(x^2+ax+a^2)[/tex]

For the given expression :

[tex]\begin{gathered} 216x^3=6x\cdot6x\cdot6x \\ \end{gathered}[/tex]

So, the factors will be :

[tex](216x^3-1)=(6x-1)(36x^2+6x+1)[/tex]