Explanation:
For any right triangle
the relationship between the hypotenuse and the adjacent side of an angle theta is the cosine of the angle:
[tex]\cos \theta=\frac{b}{a}[/tex]
In this problem we have b = 16m and a = 25m. Therefore the cosine of x is:
[tex]\cos x=\frac{16m}{25m}=0.64[/tex]
Using the inverse of the cosine - "the arc whose cosine is x" - we find x:
[tex]\begin{gathered} x=\arccos 0.64 \\ x\approx50.21º\approx0.88rad \end{gathered}[/tex]
Answer:
The value of the angle is x = 50.21º or x = 0.88 radians
