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When doing a chin-up, a student lifts her body with a force of 400N and a distance of 0.25 meters in 2 seconds. What is the power delivered by the students biceps?

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Respuesta :

Given:

The student lifts her body with a force F = 400 N

The distance is d = 0.25 N

The time is t = 2 s

To find: The power delivered by student's biceps.

Explanation:

The formula to calculate power is

[tex]P=\frac{F\times d}{t}[/tex]

Substituting the values, the power will be

[tex]\begin{gathered} P=\frac{400\times0.25}{2} \\ =\text{ 50 W} \end{gathered}[/tex]

Final Answer: The power delivered by student's biceps is 50 W.

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