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A 5.00 kilogram block is pulled 2.0 meters along a
horizontal, frictionless surface using a force of 100
newtons at an angle of 20.0° above horizontal as shown
in the diagram below. Determine the amount of work done in the block as it is moved

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Respuesta :

Answer:

188 J

Explanation:

W = F * d * cosα

Now F = 100 N, d = 2.0 m, α = 20.0°

so

W = 100 * 2.0 * cos(20) = 188 J

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