byanap4043 byanap4043
  • 24-02-2022
  • Chemistry
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The heat of vaporization of water is 40.66 kJ/mol. How much heat is absorbed when 2.23 g of water boils at atmospheric pressure?

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mererupatrick mererupatrick
  • 24-02-2022

Answer:

5.0kj

Explanation:

1mole of H2O —>40.66kj

1mole of H2O—>18g

18g of H2O—>40.66K

2.23g. —>?

2.23g×40.66kj=90.6718g/kj

90.6718g/kj÷18g

=5.0kj

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