DrippQueenMo DrippQueenMo

24-09-2021
Mathematics

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thaonguyen1 thaonguyen1

24-09-2021

Answer:

[tex]\frac{BC}{sinA} = \frac{AB}{sinC}[/tex]

-> [tex]\frac{15}{sin98^{o}} = \frac{BC}{sin (180^{o} - 98^{o} - 45^{o}) }[/tex]

-> BC = 9. 11594... -> BC ≈ 9.1

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