emmanuelalv23 emmanuelalv23

25-05-2021
Chemistry

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how many moles are in 89 grams of Pb(CH3COO)4

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jellyfish0802 jellyfish0802

25-05-2021

Answer:

0.20 moles of Pb(CH3COO)4

Explanation:

89g Pb(CH3COO)4 x 1 mol Pb(CH3COO)4 / 443.376 g Pb(CH3COO)4

= 0.20 moles of Pb(CH3COO)4

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