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1. You have a large flashlight
which uses 6 V of electricity. If
the current in the flashlight is 2
A, what is the resistance of the
light bulb?

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Respuesta :

Stephen46

Answer:

3 Ω

Explanation:

The resistance can be found by using the equation for Ohms law which is

V = IR

V is the voltage

I is the current

R is the resistance

[tex]r = \frac{v}{i} \\ [/tex]

We have

[tex]r = \frac{6}{2} = 3 \\ [/tex]

We have the final answer as

3 Ω

Hope this helps you

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