A town requiring 2.0 m3/s of drinking water has two sources, a local well with 15 g/m3 nitrate (as N) and a distant reservoir with 5 g/m3 nitrate (as N). What flow rates of well and reservoir water are needed to meet the EPA drinking water standard and minimize the use of more expensive reservoir water

Relax

Respuesta :

Explanation:

Drinking water requirement in town 2.0 m^3/s of water per second

nitrate in local well  nitrate per 15 [tex]\mathrm{m}^{3}[/tex] of water

nitrate in distant reservoir [tex]=5 \mathrm{~g} / \mathrm{m}^{3}[/tex]

Let the flow rate of well

flow rate of reservoir [tex]=y m^{3} / s[/tex]

Drinking water requirement is [tex]45 \mathrm{ppm}[/tex] or [tex]45 \mathrm{~g} / \mathrm{m}^{3}[/tex]

therefore, the total flow of drinking water