A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. Show work. y=-16x^2+200x+82

Relax

Respuesta :

Answer:

Step-by-step explanation:

y=-16x^2+200x+82

Answer:

my answer is 707

Step-by-step explanation:

Delta math told me lol