Relax

Respuesta :

Answer:

[tex]3.2 \div 22.4 = \frac{1}{7} mol \: no[/tex]

[tex]4.3 \div 32 = 0.134mol \: o2[/tex]

Explanation:

NO is limit reactant so:

1÷7×46=6.57 grams of NO2 will form