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When 29 grams of sodium metal (Na) react with 49 grams of chlorine gas (C1), solid
sodium chloride (NaCl) is created in synthesis reaction. How much excess sodium OR
chlorine is left over?

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Respuesta :

Answer:

Explanation:

Na     +     Cl    =      NaCl

23 g        35.5 g  

23 g sodium reacts with 35.5 g of chlorine

29 g of sodium reacts with 35.5 x 29 / 23 g of chlorine

= 44.76 g

So 44.76 g of chlorine reacts and 49 - 44.76 = 4.24 g of chlorine is left over .

All the sodium is used up in the reaction .

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