Answer:
Step-by-step explanation:
in Δ ADM and Δ CBM
AD║BC and AC cuts it.
so ∠DAM=∠BCM (alternate angle)
∠AMD=∠CMB ( vertically opposite angles)
AM=CM (given ,M is mid point of AC)
Hence ΔAMD ≡ ΔCMB (ASA=ASA)
AD=CB
