dbimurza19 dbimurza19

22-06-2020
Physics

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A new battery has an emf of 1,52 V. When a wire of negligible resistance is connected between the terminals of the battery, a current of 7,05 A is produced. Find the internal resistance of the battery.

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khalil2012am khalil2012am

22-06-2020

Answer:

Explanation:

r = V/i = 1.52/7.05 = 0.216 ohm

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