vanessaq vanessaq
  • 23-03-2020
  • Mathematics
contestada

A rectangle has a height of 4 and a width of 2x^2-x

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Hi1315
Hi1315 Hi1315
  • 23-03-2020

Answer:

[tex]area = 4 \times (2 {x}^{2} - x) \\ 8 {x}^{2} - 4x[/tex]

[tex]perimeter = 4 + 4 + 2 {x}^{2} - x + 2 {x}^{2} - x \\ 8 + 4 {x}^{2} - 2x[/tex]

Step-by-step explanation:

hope this helps you.

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John2003ventura
John2003ventura John2003ventura
  • 09-04-2020

Answer: 8x^2-4x

Step-by-step explanation:

Answer Link

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