did i do this right?
find the equation of the axis of symmetry for the parabola
y=x^2-8x+5

used y=ax^2+bx+c and got a=1 b=-8 and c=5

then used the formula x=-b/2a and plugged that in and got x=- -8/2(1) and simplified to get x=4 as the axis of symmetry.