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The given line passes through the points (−4, −3) and (4, 1).



What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, 3)?

y − 3 =

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ANSWER

[tex]y - 3 = - 2(x + 4)[/tex]

EXPLANATION

The slope of the line through (−4, −3) and (4, 1).

is

[tex] = \frac{1 - - 3}{4 - - 4} [/tex]
[tex] = \frac{4}{8} [/tex]
[tex] = \frac{1}{2} [/tex]

The slope of the line perpendicular to it is

[tex] - 2[/tex]

The point -slope form is given by the formula

[tex]y-y_1=m(x-x_1)[/tex]

Where
[tex](x_1,y_1)=(-4,3)[/tex]

The required equation is;

[tex]y - 3 = - 2(x + 4)[/tex]

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