The longest side of an acute isosceles triangle is 8 centimeters. Rounded to the nearest tenth , what is the smallest possible length of one of the two congruent sides?
let a---------> length of one of the two congruent sides of the triangle
we know that The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem) so (a+a) > 8 2a > 8 a> 4 Rounded to the nearest tenth, the smallest possible length of a is 4.1
