kafledebaki7
kafledebaki7 kafledebaki7
  • 26-02-2024
  • Mathematics
contestada

prove that:

[tex] \frac{1}{a {}^{2} + 2ab + b {}^{2} } + \frac{1}{a {}^{2} - 3a + 2} [/tex]
is equal to
[tex] \frac{2a + 1}{(a - 1)( a+ 3)(a - 2)} [/tex]



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